Speed problems: The Speed Table - Handling Speed Problems with Data Overload
Tammy climbed a mountain in two days. She spent a total of 14 hours climbing the mountain. On the second day, she walked at an average speed that was half a kilometer per hour faster but 2 hours less than what she walked on the first day. If the total distance she climbed during the two days is 52 kilometers, how many kilometers per hour did Tammy walk on the second day?
Incorrect.
[[snippet]]
Incorrect.
[[snippet]]
Incorrect.
[[snippet]]
Incorrect.
[[snippet]]
Before you start __Reverse Plugging In__, solve for the time $$t$$:
>$$t + (t-2) = 14$$
>$$t=8$$
Now __Plug In__ the answer choices. Answer choice C, $$ \color{red}{v+\frac{1}{2} = 4}$$ {color:red}km/hour{/color} is the only answer that fits both rows of the table.
| | SPEED (KM/H) | TIME (H) | DISTANCE (KM) |
|-------|--------------------------------|----------|---------------|
| Day 1 | $$3.5$$ | $$8$$ | $$28$$ |
| Day 2 | $$\color{red}{4}$$ | $$6$$ | $$24$$ |
| | | $$\text{Total} = 14$$ | $$\text{Total} = 52$$ |
Correct.
[[snippet]]
This is what the table looks like:
| | SPEED (KM/H) | TIME (H) | DISTANCE (KM) |
|-------|--------------------------------|----------|---------------|
| Day 1 | $$v$$ | $$t$$ | |
| Day 2 | $$\color{red}{v+\frac{1}{2}}$$ | $$t-2$$ | |
| | | $$\text{Total} = 14$$ | $$\text{Total} = 52$$ |