Probability: Outcome A OR Outcome B Means Add Probabilities

There are 12 balls in a jar: 6 red, 2 blue, and 4 green. If a single ball is drawn from the jar, then what is the probability that it is either blue or red?

Correct. [[snippet]] There are a total of 12 balls, of which 2 are blue. Therefore, the probability of drawing a blue ball is $$\frac{2}{12}$$. There are a total of 12 balls, of which 6 are red. Therefore, the probability of drawing a red ball is $$\frac{6}{12}$$. Since you need a blue ball _or_ a red ball, add the above results: >$$\text{Probability} = \frac{2}{12}+\frac{6}{12}=\frac{8}{12}=\frac{2}{3}$$.

Incorrect. [[snippet]] Did you multiply the events' probabilities? Nice try. However, this is an "or" relationship, so _add_ the probabilities.

Incorrect. [[snippet]]

Incorrect. [[snippet]]

Incorrect. [[snippet]]

$$\frac{1}{12}$$

$$\frac{1}{4}$$

$$\frac{1}{2}$$

$$\frac{2}{3}$$

$$\frac{3}{4}$$