If $$13 < 7x + 1 < 25$$, how many integer values of $$x$$ are there?

Correct.
[[Snippet]]
Subtract 1 from the inequality to isolate $$7x$$.
>$$13 - 1 < 7x + 1 - 1 < 25 - 1$$
>$$12 < 7x < 24$$
Divide the inequality by 7 to isolate $$x$$.
>$$\frac{12}{7} < \frac{7x}{7} < \frac{24}{7}$$
>$$\frac{12}{7} < x < \frac{24}{7}$$
Based on this, $$x$$ is more than 1 ($$\frac{7}{7} = 1$$, so $$\frac{12}{7}$$ is greater) and less than 4 ($$\frac{28}{7}=4$$, so $$\frac{24}{7}$$ is smaller). In other words, the integer values of $$x$$ are 2 and 3. Hence, there are two possible integer values for $$x$$.

Incorrect.
[[snippet]]
Carefully check your calculations.

Incorrect.
[[snippet]]
Carefully check your work.

Incorrect.
[[snippet]]
Solve the given inequality for $$x$$.

Incorrect.
[[snippet]]
You need to solve the inequality $$13 < 7x + 1 < 25$$ for $$x$$.

1

2

3

4

5