Table Analysis - Calculating
For each of the following statements, select Yes if the statement can be shown to be true based on the information in the table. Otherwise, select No.
Yes!
Look at the column labeled "Percent Free or RP of Total." This column shows the number of lunches served that were either free or reduced price.
In this column, notice that less than 50% of lunches served were free or reduced price in exactly four of the years listed: 1975, 1980, 1985, and 1990. Thus, in those years and only those years, full-price lunches accounted for more than 50% of total lunches served.
Therefore, the statement is false: in only four (not five) of the years listed did full-price lunches account for more than half of lunches served.
Incorrect.
Look at the column labeled "Percent Free or RP of Total." This column shows the number of lunches served that were either free or reduced price.
In this column, notice that less than 50% of lunches served were free or reduced price in exactly four of the years listed: 1975, 1980, 1985, and 1990. Thus, in those years and only those years, full-price lunches accounted for more than 50% of total lunches served.
Therefore, the statement is false: in only four (not five) of the years listed did full-price lunches account for more than half of lunches served.
Incorrect.
First find the number of students receiving reduced-price lunches in 2000 and 2010 by looking at the column labeled "Reduced Price." - In 2000, 2.5 million students received reduced-price lunches. - In 2010, 3 million students received reduced-price lunches. Next, use the formula for percent change to calculate the percent increase. $$\displaystyle\mbox{Percent change} = \frac{\mbox{Difference}}{\mbox{Original}} \cdot 100\%$$ For this problem, the difference is $$3 - 2.5 = 0.5 ~\mbox{million}$$ and the original value is 2.5 million. Calculate the percent increase. $$\frac{0.5}{2.5} \cdot 100\% = 20\%$$ Therefore, the statement is true.That is correct!
First calculate the number of free or reduced-price lunches served in 1975 and 2015. To do this, multiply the value in the "Total Lunches Served" column by the value in the "Percent Free or RP of Total" column for 1975 and 2015.
In 1975, there were 4.063 billion lunches served. Of those, about 40.3% were free or reduced price. You can ballpark the number of free or reduced-price lunches as $$40\% ~\mbox{of}~ 4 = 0.4 \cdot 4 = 1.6 ~\mbox{billion}$$. In 2015, there were 5.003 billion lunches served and about 72.6% of them were free or reduced price. Thus, the number of free or reduced-price lunches was about $$70\% ~\mbox{of}~ 5 = 0.7 \cdot 5 = 3.5 ~\mbox{billion}$$.
Incorrect.
First calculate the number of free or reduced-price lunches served in 1975 and 2015. To do this, multiply the value in the "Total Lunches Served" column by the value in the "Percent Free or RP of Total" column for 1975 and 2015.
In 1975, there were 4.063 billion lunches served. Of those, about 40.3% were free or reduced price. You can ballpark the number of free or reduced-price lunches as $$40\% ~\mbox{of}~ 4 = 0.4 \cdot 4 = 1.6 ~\mbox{billion}$$. In 2015, there were 5.003 billion lunches served and about 72.6% of them were free or reduced price. Thus, the number of free or reduced-price lunches was about $$70\% ~\mbox{of}~ 5 = 0.7 \cdot 5 = 3.5 ~\mbox{billion}$$.
