Percents: Percent Change
A department store's annual revenue in 2010 was $240,000. Following an advertising campaign, the store's revenue increased in 2011 to a sum of $288,000. What is the percent increase, to the nearest percent, of the store's annual revenue between 2010 and 2011?
Incorrect.
Good job with the math, but you solved the wrong question . . .
Remember, because the question describes a percent increase, the original is the smaller number.
Incorrect.
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Incorrect.
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Correct.
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Because the question describes a percent increase, the original is the smaller number (the $240,000). Therefore, using the percent change formula:
>$$\displaystyle Percent~ change= \frac{288{,}000-240{,}000}{240{,}000} \cdot 100= \frac{48{,}000}{240{,}000} \cdot 100$$
Reduce three 0s in the fraction, and:
> $$\displaystyle Percent~ change = \frac{48}{240} \cdot 100$$
Reduce another 0 from the denominator with 0 from the 100 to get:
> $$\displaystyle Percent~ change = \frac{48}{24} \cdot 10 = 2 \cdot 10 = 20\%$$
Incorrect.
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40%
30%
20%
17%
10%
