Graphics Interpretation - Bar Graph Iterations

The graph shows the number of fish a fisherman catches in three years, broken down by fish type and year.

From each drop-down menu, select the option that creates the most accurate statement based on the information provided.

In 2012, the fisherman caught a total of [[dropdown1]] fish.

Between 2013 and 2014, the greatest percent increase in fish was for [[dropdown2]] .

Incorrect. To calculate the percent increase for each type of fish, use the graph to find the number of each fish in 2013 and 2014 and then apply the following formula. $$\mbox{Percent change} = \frac{\mbox{Difference}}{\mbox{Original}} \cdot 100\%$$ The number of bass increases from 200 to 225, so the difference is 25 and the original is 200. Use this to calculate the percent increase. $$\frac{25}{200} \cdot 100\% \approx 13\%$$ This is _not_ the greatest percent increase of the four fish.

Incorrect.

You might have gotten this answer if you found the total number of fish in 2013, instead of 2012.

Use the blue bars to calculate the number of each type of fish that the fisherman catches in 2012. Then add up these values.

That's right!

Use the blue bars to calculate the number of each type of fish that the fisherman catches in 2012.

• Bass: 250

• Catfish: 100

• Minnow: 450

• Pike: 300

Then add up these values.

$$250 + 100 + 450 + 300 = 1{,}100$$

Incorrect.

You might have gotten this answer if you did not include the number of pike caught in 2012 in your calculation.

Use the blue bars to calculate the number of each type of fish that the fisherman catches in 2012. Then add up these values.

Alternatively, you can compare the fractions themselves. Since $$\frac{25}{200}$$ and $$\frac{25}{125}$$ have the same numerator, $$\frac{25}{125}$$ must be greater since its denominator is smaller. Now compare $$\frac{25}{125}$$ and the last fraction, $$\frac{50}{150}$$. Their denominators are close, but the numerator of $$\frac{50}{150}$$ is _twice_ the numerator of $$\frac{25}{125}$$. Therefore, you can be sure that $$\frac{50}{150} > \frac{25}{125}$$. Thus, $$\frac{50}{150}$$ is the greatest of the three fractions.

Incorrect.

To calculate the percent increase for each type of fish, use the graph to find the number of each fish in 2013 and 2014 and then apply the following formula.

$$\mbox{Percent change} = \frac{\mbox{Difference}}{\mbox{Original}} \cdot 100\%$$

The number of minnow actually decreases, so it cannot be the correct answer.

Incorrect. To calculate the percent increase for each type of fish, use the graph to find the number of each fish in 2013 and 2014 and then apply the following formula. $$\mbox{Percent change} = \frac{\mbox{Difference}}{\mbox{Original}} \cdot 100\%$$ The number of catfish goes from 125 to 150, so the difference is 25 and the original is 125. Use this to calculate the percent increase. $$\frac{25}{125} \cdot 100\% = 20\%$$ This is _not_ the greatest percent increase of the four fish.

That's right!

To calculate the percent increase for each type of fish, use the graph to find the number of each fish in 2013 and 2014 and then apply the following formula.

$$\mbox{Percent change} = \frac{\mbox{Difference}}{\mbox{Original}} \cdot 100\%$$

$$\frac{25}{200} \cdot 100\% \approx 13\%$$ The number of catfish goes from 125 to 150, so the difference is 25 and the original is 125. $$\frac{25}{125} \cdot 100\% = 20\%$$ The number of minnow decreases, so you can rule it out. The number of pike goes from 150 to 200, so the difference is 50 and the original is 150. $$\frac{50}{150} \cdot 100\% = 33\%$$ Thus, the answer is pike because it has the greatest percent increase.

400

775

1,100

bass

catfish

minnow

pike

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