If $$S$$ is a sequence of consecutive multiples of 7, then how many multiples of 14 are in $$S$$?
>(1) The greatest term in $$S$$ is even.
>(2) There are 21 terms in $$S$$.

Correct.
[[snippet]]
Although stat. (1) provides a valuable piece of the puzzle, it leaves the actual number of terms in the set open. Alone, **Stat.(1) → IS → BCE**.
Stat. (2) provides the number of terms in the set. However, since this number is odd, there are still two possible cases, based on whether the first and last term are multiples of 14 or not. Thus, no single answer can be determined, so **Stat.(2) → IS → CE**.
For stat. (1+2), since the last term is even and also a multiple of 7, you can deduce that it is a multiple of $$2\times 7=14$$. Therefore, the two statements combined determine a single case: there are 21 terms (an odd number), out of which the first and last term is a multiple of 14. The number of multiples of 14 in set $$S$$ can therefore be determined (not that you really have to), and thus **Stat.(1+2) → S → C**.

Incorrect.
[[snippet]]
Although stat. (1) provides a valuable piece of the puzzle, it leaves the actual number of terms in the set open. Alone, **Stat.(1) → IS → BCE**.

Incorrect.
[[snippet]]
Stat. (2) provides the number of terms in the set. However, since this number is odd, there are still two possible cases, based on whether the first and last term are multiples of 14 or not. Thus, no single answer can be determined, so **Stat.(2) → IS → ACE**.

Incorrect.
[[snippet]]
Although stat. (1) provides a valuable piece of the puzzle, it leaves the actual number of terms in the set open. Alone, **Stat.(1) → IS → BCE**.
Stat. (2) provides the number of terms in the set. However, since this number is odd, there are still two possible cases, based on whether the first and last term are multiples of 14 or not. Thus, no single answer can be determined, so **Stat.(2) → IS → CE**.

Incorrect.
[[snippet]]
For stat. (1+2), since the last term is even and also a multiple of 7, you can deduce that it is a multiple of $$2\times 7=14$$. Therefore, the two statements combined determine a single case: there are 21 terms (an odd number), out of which the first and last term is a multiple of 14. The number of multiples of 14 in set $$S$$ can therefore be determined (not that you really have to), and thus **Stat.(1+2) → S → C**.

Statement (1) ALONE is sufficient, but Statement (2) alone is not sufficient to answer the question asked.

Statement (2) ALONE is sufficient, but Statement (1) alone is not sufficient to answer the question asked.

BOTH Statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked.

EACH statement ALONE is sufficient to answer the question asked.

Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data specific to the problem are needed.