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# Powers: Basic Rules - Raising a Power to Another Power

If $$6^x > 216^2$$, what is the least possible integer value of $$x$$?
Correct. [[Snippet]] Since $$216 = 6 \cdot 36 = 6 \cdot 6 \cdot 6$$, you can express $$6^x > 216^2$$ as >$$6^x > (6^3)^2$$ >$$6^x > 6^6$$. Since the bases are the same, ignore the bases and compare the exponents. >$$x > 6$$ Hence, the least possible integer value of $$x$$ is 7.
Incorrect. [[Snippet]]
Incorrect. [[Snippet]]
Incorrect. Note that the question uses an inequality, not an equation. [[Snippet]]
Incorrect. [[Snippet]]
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