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Fractions: Denominator Dynamics

If $$2 \le x \le 7 $$and $$6 \lt y \lt 15$$, which of the following CANNOT be a value of $$\frac{x}{y}$$?
Correct. [[Snippet]] Since $$y$$ cannot be 16, $$\frac{x}{y}$$ cannot be $$\frac{2}{16} = \frac{1}{8}$$, so this is the correct answer.
Incorrect. [[Snippet]] Since $$\frac{1}{3}$$ is greater than $$\frac{2}{15}$$, (__Ballpark__ $$\frac{2}{15}$$ as $$\frac{2}{16}=\frac{1}{8}$$), $$\frac{x}{y}$$ can be $$\frac{1}{3}$$, and this is not the correct answer.
Incorrect. [[Snippet]] Since $$\frac{2}{7}$$ is greater than $$\frac{1}{8}$$, $$\frac{x}{y}$$ can be $$\frac{2}{7}$$, and this is not the correct answer.
Incorrect. [[Snippet]] Since $$\frac{2}{13}$$ is greater than $$\frac{2}{15}$$, $$\frac{x}{y}$$ can be $$\frac{2}{13}$$, and this is not the correct answer.
Incorrect. [[Snippet]] Since $$\frac{1}{5}$$ is greater than $$\frac{2}{15}$$ (which is $$\frac{1}{7.5}$$), $$\frac{x}{y}$$ can be $$\frac{1}{5}$$, and this is not the correct answer.
$$\frac{1}{3}$$
$$\frac{2}{7}$$
$$\frac{1}{5}$$
$$\frac{2}{13}$$
$$\frac{1}{8}$$