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# Data Sufficiency: Yes/No Basic Technique

Is $$x$$ closer to $$20$$ than to $$35$$? >(1) $$35 - x \gt x - 20$$ >(2) $$x\gt 26$$
Incorrect. [[snippet]] Stat. (1): solve the given inequality: >$$35 - x \gt x - 20$$ >$$55 \gt 2x$$ >$$27.5 \gt x$$. Given that $$x$$ is less than 27.5, it is closer to 20 than 35. This is a definite answer, so **Stat.(1) → S → AD**.
Incorrect. [[snippet]] Stat. (2): $$x$$ can be 27 (less than the midpoint, so closer to 20) or 30 (greater than the midpoint, so closer to 35), or even greater than 35. There is no definite answer, so **Stat.(2) → IS → ACE**.
Incorrect. [[snippet]] Stat. (1): solve the given inequality: >$$35 - x \gt x - 20$$ >$$55 \gt 2x$$ >$$27.5 \gt x$$. Given that $$x$$ is less than 27.5, it is closer to 20 than 35. This is a definite answer, so **Stat.(1) → S → AD**.
Incorrect. [[snippet]] Stat. (2): $$x$$ can be 27 (less than the midpoint, so closer to 20) or 30 (greater than the midpoint, so closer to 35), or even greater than 35. There is no definite answer, so **Stat.(2) → IS → ACE**.
Correct. [[snippet]] Stat. (1): solve the given inequality: >$$35 - x \gt x - 20$$ >$$55 \gt 2x$$ >$$27.5 \gt x$$. Given that $$x$$ is less than 27.5, it is closer to 20 than 35. This is a definite answer, so **Stat.(1) → S → AD**. Stat. (2): $$x$$ can be 27 (less than the midpoint, so closer to 20) or 30 (greater than the midpoint, so closer to 35), or even greater than 35. There is no definite answer, so **Stat.(2) → IS → A**.
Statement (1) ALONE is sufficient, but Statement (2) alone is not sufficient to answer the question asked.
Statement (2) ALONE is sufficient, but Statement (1) alone is not sufficient to answer the question asked.
BOTH Statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked.