$$\left(\sqrt[5]{25}\right)^5 = $$

Correct.
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First, convert the root to a fractional power, keeping in mind that the index of the root is the denominator of the exponent.
> $$\left(\sqrt[5]{25}\right)^5 = \left(25^{\frac{1}{5}}\right)^5$$
Now use the rules of raising a power to an exponent: multiply the exponents.
> $$\left(25^{\frac{1}{5}}\right)^5 = 25^{\frac{1}{5} \cdot5} = 25^{\frac{5}{5}} = 25^1 = 25$$
Hence, this is the correct answer.

Incorrect.
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$$2$$

$$\sqrt{5}$$

$$5$$

$$25$$

$$125$$