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Inequalities: Simultaneous Inequalities

If \$\$-32 ≤ x ≤ 14\$\$ and \$\$-17 ≤ y ≤ 11\$\$, which of the following inequalities gives all possible values of \$\$x-y\$\$?

Correct.

[[snippet]] Subtract maximum \$\$y\$\$ (i.e., \$\$11\$\$) from minimum \$\$x\$\$ (i.e., \$\$-32\$\$) to get the minimum value of \$\$x-y\$\$. >\$\$-32 - 11 = -43\$\$ Likewise, subtract minimum \$\$y\$\$ (i.e., \$\$-17\$\$) from maximum \$\$x\$\$ (i.e., \$\$14\$\$) to get the maximum value of \$\$x-y\$\$. >\$\$14 - (-17) = 14 + 17 = 31\$\$ Hence, the minimum and maximum values of \$\$x-y\$\$ are \$\$-43\$\$ and \$\$31\$\$, respectively.

Incorrect.

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Incorrect.

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Incorrect.

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Incorrect.

[[snippet]] This answer is the result of directly subtracting inequalities, which is not allowed. The only operation you allowed to do to combine inequalities is addition.
\$\$-31 \le x-y \le 43\$\$
\$\$-43 \le x-y \le 31\$\$
\$\$-21 \le x-y \le 31\$\$
\$\$-15 \le x-y \le 3\$\$
\$\$-49 \le x-y \le 25\$\$