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Triangles: Isosceles

If $$AD = DB$$, $$DC =CB$$, and angle $$ABC = 90º$$ as shown above, then what is the value of $$xº$$?
Correct. [[snippet]] Given that $$CB = CD$$, > $$\displaystyle{\angle CBD = \angle CDB = \frac{180º - 100º}{2} = 40º}$$. Given that angle $$ABC$$ is a right angle, $$\angle DBA = 90º - 40º = 50º$$. Since $$AD = DB$$, $$\angle DAB = \angle DBA$$. Hence, $$xº=50º$$.
Incorrect. [[snippet]]
Incorrect. [[snippet]]
Incorrect. [[snippet]]
Incorrect. [[snippet]]
$$40º$$
$$50º$$
$$65º$$
$$80º$$
$$100º$$