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# Triangles: Isosceles If \$\$AC = AB\$\$, what is the value of \$\$x^\circ\$\$?
Incorrect. [[snippet]] It's a trap! Did you take angle \$\$ABC\$\$ to be equal to angle \$\$BAC\$\$ (\$\$x^\circ\$\$)? Look at the triangle carefully: \$\$AB = AC\$\$ so \$\$\angle ABC = \angle ACB\$\$.
Incorrect. [[snippet]]
Incorrect. [[snippet]]
Correct. [[snippet]] Since \$\$AB = AC\$\$, \$\$\angle ABC = \angle ACB = 58^\circ\$\$. Based on this, > \$\$x^\circ + 58^\circ + 58^\circ = 180^\circ\$\$ > \$\$x^\circ = 180^\circ - 2(58^\circ) = 64^\circ\$\$.
Incorrect. [[snippet]] Did you take angle \$\$ACB\$\$ to be equal to angle \$\$BAC\$\$? Look at the triangle carefully: \$\$AB = AC\$\$ so \$\$\angle ABC = \angle ACB\$\$.
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