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# Triangles: Isosceles

If $$BD=DA = EA = CE$$ as shown above, what is the value of $$x$$?
Correct. [[snippet]] Lines $$AD$$ and $$AE$$ are equal so angles $$ADE$$ and $$AED$$ are equal, and > $$\displaystyle \angle ADE = \angle AED = \frac{180º-40º}{2} = 70º$$. Since $$BDA$$ is a supplementary angle of angle $$ADE$$, angle $$BDA = 180º - 70º = 110º$$. Based on this, > $$\displaystyle{xº = \frac{180º - 110º}{2} = 35º}$$.
Incorrect. [[snippet]]
Incorrect. [[snippet]]
Incorrect. [[snippet]]
Incorrect. [[snippet]]
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