If $$BD=DA = EA = CE$$ as shown above, what is the value of $$x$$?

Correct.
[[snippet]]
Lines $$AD$$ and $$AE$$ are equal so angles $$ADE$$ and $$AED$$ are equal, and
> $$\displaystyle \angle ADE = \angle AED = \frac{180º-40º}{2} = 70º$$.
Since $$BDA$$ is a supplementary angle of angle $$ADE$$, angle $$BDA = 180º - 70º = 110º$$. Based on this,
> $$\displaystyle{xº = \frac{180º - 110º}{2} = 35º}$$.

Incorrect.
[[snippet]]

Incorrect.
[[snippet]]

Incorrect.
[[snippet]]

Incorrect.
[[snippet]]

15

20

25

30

35